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Problem

Submissions

Odd Even

Contributed by

Sachin_f78a

Easy

0/40

Avg time to solve 10 mins

Success Rate 86 %

1 upvotes

Problem Statement

Alice has two numbers, 'X' and 'Y'. He is asked to perform the following operations any number of times.

Alice adds 1 to 'X' if 'X' is odd. Alice adds 2 to 'X' if 'X' is even. Will he be able to make 'X' equal to 'Y'?

Return 1 if 'X' can be made equal to 'Y' using the above operations any number of times(possibly 0) and 0 otherwise.

Note: Assume 1-based indexing.

For example:

Let 'X' = 3 and 'Y' = 6, Alice adds 1 to 'X' since 'X' is odd. Now 'X' will become 4. Then, Alice will add 2 to 'X', since 'X' is even, and it will become 6. 'X' becomes equal to 'Y'. Hence we will return 1 as the answer.

Detailed explanation ( Input/output format, Notes, Constraints, Images )

Input Format:-

The first line contains an integer 'T', which denotes the number of test cases.
For every test case:-
The first line contains two integers, 'X' and 'Y', the variables mentioned above.

Output Format:-

For each test case, Return 1 if 'X' can be made equal to 'Y' using the above operations any number of times(possibly 0) and 0 otherwise.

Note:-

You don’t need to print anything. Just implement the given function.

Constraints:-

1 <= 'T' <= 10
1 <= 'X', 'Y' <= 10^9
Time Limit: 1 sec

Sample Input 1:-

2
4 8
1 1

Sample Output 1:-

1
1

Explanation of sample input 1:-

First test case:- 
In 1st operation, Alice will add 2 to 'X' as 'X' is even. Now, 'X' is 6. Again, in the 2nd operation, Alice will add 2 to 'X'. Now 'X' is 8, which is equal to 'Y'. So, the answer is 1.

Second test case:-
'X' is already equal to 'Y'. So, the answer is 1.

Sample Input 2:-

2
4 9 
7 8

Sample Output 2:-

0
1

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