Minimum and Maximum of two integers without branching.

You have been given two integers ‘a’ and ‘b’ return minimum and maximum of both the numbers without branching.

Note:

1. Branching includes if-else statements, the ternary operator, or switch-case statements. Therefore you should not use any of the above approaches to solving the problem.
2. You do not need to print anything; it has already been taken care of. Just implement the function.

Input Format:

The first line contains a single integer ‘T’ representing the number of test cases.

The only line of each test case contains two space-separated integers ‘a’ and ‘b’ representing two integers whose minimum and the maximum you need to return.

Output Format:

For each test case return the minimum and maximum of two numbers.

Constraints:

1 <= T <= 1000
1 <= ‘a’ <= 10^9
1 <= ‘b’ <= 10^9

Where ‘T’ is the number of test cases. ‘a’ and ‘b’ are the numbers whose minimum and the maximum you have to compute.  

Time Limit: 1sec

Sample Input 1:

4
1 1
2 1
17 13
11 24

Sample Output 1:

1 1
1 2
13 17
11 24

Sample Output 1 Explanation:

Test case 1:

1 is the minimum of the two numbers.1 is the maximum of the two numbers. Therefore the answer is 1 1.

Test case 2:

1 is the minimum of the two numbers.2 is the maximum of the two numbers. Therefore the answer is 1 2.

Test case 3:

13 is the minimum of the two numbers.17 is the maximum of the two numbers. Therefore the answer is 13 17.

Test case 4:

11 is the minimum of the two numbers.24 is the maximum of the two numbers. Therefore the answer is 11 24.

Sample Input 2:

2
15 20
4 3

Sample Output 2:

15 20
3 4