Problem of the day
Vertices are numbered through 0 to V - 1.
The first line contains a single integer ‘T’ denoting the number of test cases. Then each testcase follow.
The first line of each test case contains two integers ‘V’ and ‘E’ denoting the number of vertices and edges in the graph.
The next ‘E’ lines of the test case contain two space-separated integers ‘a’ and ‘b’ denoting that there exists an edge between ‘a’ and ‘b’.
The last line of the test case contains two space-separated integers ‘v1’ and ‘v2’ denoting the starting vertex and ending vertex.
For each test case, print the path from ‘v1’ to ‘v2’ in reverse order.
Output for each test case will be printed in a separate line.
You are not required to print anything; it has already been taken care of. Just implement the function and return a list of paths.
If there is no path between the vertices return an empty list.If the path is valid then it will print true else it will print false.
1 <= T <= 10
1 <= V <= 1000
1 <= E <= (V * (V - 1)) / 2
0 <= v1, v2 <= V-1
Time Limit: 1sec
2
4 4
0 1
0 3
1 2
2 3
1 3
6 3
5 3
0 1
3 4
0 3
true
false
In the first test case, there are two paths from 1 to 3. I.e. 1 -> 2 -> 3 or 1 -> 0 -> 3. So you can print any one of them.
In the second test case, there is no path from 0 to 3. Hence return an empty string.
2
2 1
0 1
1 0
5 4
0 1
1 2
2 3
3 4
0 4
true
true