Detect Odd

You are given an array of ‘N’ non-negative integers where all elements appear an even number of times except two, print the two odd occurring elements in increasing order. It may be assumed that the size of the array is at-least two and there will always be exactly two numbers which appear an odd number of times in the given array.

EXAMPLE:

Input: 'N' = 6, 'NUMS' = [1, 1, 2, 3, 4, 4]
Output: 2 3

Here in the given array we can see that 2 and 3 occur 1 time which is an odd number. Hence, the output will be 2 and 3.

Input Format :

The first line of the input contains an integer, 'T’, denoting the number of test cases.

The first line of each test case will contain a single integer ‘N’, denoting the size of the array.

The second line of each test case contains ‘N’ space-separated integers denoting elements of the array.

Output format :

For each test case, print the two numbers in increasing order separated by space which appear an odd number of times in the given array.

Note :

You don't need to print anything. It has already been taken care of. Just implement the given function.

Constraints :

1 <= 'T' <= 10
2 <= 'N' <= 10^4
1 <= 'NUMS[i]' <= 10^5

Time Limit: 1 sec

Sample Input 1 :

2
6
1 1 2 3 4 4
2
1 2

Sample Output 1 :

2 3
1 2

Explanation Of Sample Input 1 :

For the first test case,
'N' = 6 and 'NUMS' = [1, 1, 2, 3, 4, 4]
Here in the given array we can see that 2 and 3 occur 1 time which is an odd  number. Hence, the output will be 2 and 3.

For the second test case,
'N' = 2 and 'NUMS' = [1, 2]
Here in the given array we can see that 1 and 2 occur 1 time which is an odd  number. Hence, the output will be 1 and 2.

Sample Input 2 :

2
4
8 2 2 7
4
3 1 3 5

Sample Output 2 :

7 8   
1 5