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# Boxes Of Chocolates

Difficulty: MEDIUM
Contributed By
Pankaj Sharma
Avg. time to solve
20 min
Success Rate
86%

Problem Statement

#### For Example: for the given boxes of chocolates [3,2,2,5,4,1] and 5 students.

Output: 2

If there is no restriction on choosing the boxes then the maximum number of chocolates the 5 students equally can have is 3 by picking all boxes except the box at index 2(0-based indexing). So total candies will be 3+2+5+4+1 = 15 and each of the 5 students will get 15/5=3 candies.

But we are allowed to choose only consecutive boxes. So if we choose boxes [0,1] then 3+2=5 then each student will have only 1 chocolate and when we choose boxes[4,6] as 5+4+1=10 then each student will have 2 chocolates. So the maximum number of chocolates each student can get is 2.
##### Input Format:
The first line of input contains a single integer T, representing the number of test cases or queries to be run.

Then the T test cases follow.

The first line of each test case contains two single space-separated integers N, and K, denoting the total number of boxes and the total number of students respectively.

The second line of each test case contains 'N' single space-separated integers representing the count of chocolates in each of the N boxes.
##### Output Format:
For each test case, print an integer denoting the maximum number of chocolates each child can get in a single line
##### Constraints:
1 <= T <= 10
1 <= N <= 10^5
1 <= K <= 10^5
0 <= boxes[i] <= 10^5

Time Limit: 1 sec
2
5 3
1 2 3 4 5
5 4
1 2 3 4 5
5
3
##### Explanation for Sample 1:
For the first test case, we can choose the boxes [0,4] as 1+2+3+4+5=15  each student will have 5 chocolates.

For the second test case, You can choose the boxes [2, 4] as 3+4+5=12, each student will have 3 chocolates.
1
5 8
1 2 3 4 5
0
##### Explanation for Sample 2:
For the first test case, there is no way to choose consecutive boxes and divide chocolates from those boxes equally among 8 students
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