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# Remainder When Divided By 11

Last Updated: 5 Jan, 2021
Difficulty: Easy

## PROBLEM STATEMENT

#### You are given a number N. You need to find the remainder when N is divided by 11.

##### Note :
``````Number N may be very large.
``````
##### Input format :
``````The first line contains an integer 'T' denoting the number of test cases to be run. The 'T' test cases follow.

The first line of each test case contains a single number 'N' in the form of a string.
``````
##### Output Format :
``````For each test case, print an integer denoting the remainder when 'N' is divided by 11.
``````
##### Constraints :
``````1 <= T <= 5
1 <= length of N <= 10 ^ 6

Time Limit: 1 sec
`````` ## Approach 1

1. Since the number is very large we can not simply calculate N % 11.
2. Now, any number say 256 % 11 can be calculated as (25*10 + 6)%11. Which in turn can be calculated as (( 25*10)%11+ 6)%11 or ( (25%11)*10 + 6)%11. Similarly 25%11 can be calculated as (2*10+5)%11. Therefore , 256 %11 can be finally calculated as ( ( (2*10 + 5)%11 )*10 + 6)%11.
3. So, the idea is to store the number N in string Str.
4. Take a variable Num, initialize it with 0.
5. Now iterate character by character over the string and convert it into a digit, starting from 0th index.
6. Multiply your current Num by 10 and add the current digit, say b, in it and then take it modulus with 11. So Num becomes Num = (Num*10 + b)%11.
7. The final value of Num will be the required remainder.