Mean Median Mode

PROBLEM STATEMENT

You are given an array 'ARR' of 'N' integers and you have to calculate 3 things for the given array:-

1. Mean - function mean(): This function should calculate the mean of the array.

2. Median - function median(): This function should calculate the median of the array.

3. Mode - function mode(): This function should calculate the mode of the array.

Note :

It can be shown that Mean and Median is in the form of P/Q, where P and Q are coprime integers and Q != 0. You need to return P and Q.

For Mode, if the highest frequency of more than one element is the same, return the smallest element.

For Example, for the given array {1, 1, 2, 2, 3, 3, 4}, the mode will be 1 as it is the smallest of all the possible modes i.e 1, 2 and 3.

Input format :

The first line of input contains an integer T denoting the number of queries or test cases. 

The first line of every test case contains an integer N denoting the size of the input array.

The second line of every test case contains N single space-separated integers representing the elements of the input array.

Output format :

For each test case, 
The first line of output will contain 2 single space-separated integers representing P, and Q for the Mean of the array.

The second line of output will contain 2 single space-separated integers representing P, and Q for the Median of the array.

The third line of the output will contain an integer representing the Mode of the array.

Note :

You do not need to print anything, it has already been taken care of. Just implement the given functions.

Constraints :

1 <= T <= 5
1 <= N <= 10^5 
1 <= ARR[i] <= 10^6 

Where 'ARR[i]' denotes the 'ith' element of the array.

Time limit: 1 sec

Approach 1

For the mean and median of the array, we will first calculate both the results in N / D form where N denotes the numerator of the result and D denotes the denominator. Then for the P/ Q form where P and Q should be coprime, we will find the gcd of (N, D) and divide both N and D by the gcd. Thus P = N / gcd(N,D) and Q = D / gcd(N, D).

For the mean,

Maintain the sum of the array elements and store it in a variable say Sum.
Using the formulae Mean = (Sum of elements ) / ( Count of elements ), where N = Sum and D = Count. divide the Sum by N and return the answer.

For the median,

Sort the array in ascending order.
If the number of elements (N) is odd, Median is the (N+1)/2 th element. Thus N = array[(N+1)/2] and D = 1
If the number of elements (N) is even, Median is the average of N/2th and (N/2 + 1)th element. Thus N = array[N/2] + array[(N+1)/2] and D = 2

For mode,