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Let `" " p(t)=5t^(2)+12t+7=5t^(2)+5t+7t+7` <br> `=5t(t+1)+7(t+1)=(t+1)(5t+7)` <br> `:. " " p(t)=0` <br> `implies " " (t+1)(5t+7)=0` <br> `implies " " t+1=0 " " or " " 5t+7=0` <br> `implies " " t=-1 " " or " " t=-(7)/(5)` <br> `:.` Zeroes of p(t) are -1 and `-(7)/(5)`. <br> Now, sum of zeroes `=(-1)+(-(7)/(5))=-(12)/(5)=-("coefficient of" t)/("coefficient of" t^(2))" "` Hence Verified. **Definition and Degree of polynomial**

**Types of polynomial : Constant ; Linear; Quadratic; Cubic and Bi-quadratic Polynomial**

**Value of a polynomial**

**Zeros or roots of polynomial**

**Steps to draw a graph of a polynomial**

**Graph of Linear polynomial**

**Graph of quadratic polynomial When polynomial is factorable into two distinct factors**

**Graph of quadratic polynomial When polynomial have no zeroes**

**Graph of quadratic equation when coefficient of highest degree is negative**

**Graph of quadratic when coefficient of `x^2` is > 1**