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Bit Insertion

Posted: 21 Feb, 2021
Difficulty: Easy


Try Problem

You are given two 32 bit positive integers 'X' and 'Y', and two positions 'A' and 'B'. Your task is to insert 'Y' into 'X' starting from A’th position to B’th position both inclusive.

Inserting a number is resetting all the bits of 'X' from position 'A' to position 'B' and then writing 'Y' in 'X' starting from index 'A'.

Note : Bit positions are 0 indexed.

For example :
X = 1536 and Y = 7, A = 1 and B = 5,
X is base 2 = 11000000000, Y in base 2 = 0111
First, we clear all the birts of X from index 1 to index 5 then wrote Y in X starting from A.
After inserting Y in X starting from position result will be 11000001110
Input Format :
The first line of input contains an integer 'T’ denoting the number of test cases to run. Then the test case follows.

The first and the only line of each test case contain four single space-separated integers ‘X’, ‘Y’, ‘A’, and ‘B’ denoting the integers and the starting and the ending positions for insertion, respectively. 
Output Format :
For each test case print the number 'X' after inserting the 'Y' from A’th to B’th position.
Output for each test case is printed in a separate line.
Note :
You don’t need to print anything. It has already been taken care of. Just implement the given function.
Constraints :
1 <= T <= 5000
1 <= X,Y <= 2^31
0 <= A <= B < 32 

‘X’, ‘Y’, ‘A’, ‘B’ are two given integers and starting bit positions and ending bit position to insert respectively.
It is guaranteed that the position from ‘A’ to  ‘B’ is enough to insert Y.
Time Limit : 1 sec