Step 1: int right(0) initializing right as zero and left(0) initializing left as zero
taking sum of all the element and assigning it to right
Step 2: running a loop through the whole array from left to right (i=0 --> n-1)
Step 3: at every step to find the if right sum = left sum we subtract current element from the array i.e. nums[i]
hence right-=nums[i]
Step 4: by implementin...

Using HashMap

First we will create map for counting frequencies of each element in the array.

Now we have 2 cases over here as
-->a) if k == 0 it means we need to count frequency of the same element by using map.get(i) method.
-->b) we need to take counter approach for every element by adding k everytime and check whether that element is present in map or not.

I...