# Amazon Interview Experience for Fresher SDE - 1, Jan 2019

Posted: 28 Jul 2020
465
Selected
Interview Rounds
Application Process

## Interview Process

### Online Coding Test

Easy
Duration:
60 minutes
Interview-Date:
25 Jan 2019
Problems:
2
Tiling Problem

Given a “2 x n” board and tiles of size “2 x 1”, count the number of ways to tile the given board using the 2 x 1 tiles. A tile can either be placed horizontally i.e., as a 1 x 2 tile or vertically i.e., as 2 x 1 tile.

Examples:

Input n = 3

Output: 3

Explanation:

We need 3 tiles to tile the board of size  2 x 3.

We can tile the board ...

View more
Find k’th character of decrypted string

Given an encoded string where repetitions of substrings are represented as substring followed by count of substrings. For example, if encrypted string is “ab2cd2” and k=4 , so output will be ‘b’ because decrypted string is “ababcdcd” and 4th character is ‘b’.

Note: Frequency of encrypted substring can be of more than one digit. For example, in “ab12c3”, ab is repeated 12 time...

View more
Next
Round - 2

## Preparation

Duration:
8 months
Topics:
Data Structures and Algorithms, Operating System, Database Management System, Object-Oriented Programming System
Preparation Tip

Do lot of hard work and practice of  Data Structures and Algorithms based questions. I personally recommend you Coding Ninjas and Geeks For Geeks for interview preparation.

## Application Process

Where:
Campus
Eligibility:
7 CGPA
Resume Tip

Make your resume short and try to make it of one page only and do mention all your skills which you are confident of in your resume.

Have an interview experience that you want to contribute?
PreviousNext
Join the Discussion
11 replies
12 Nov 2020
Edited

Thank You So much. For the splitwise question DP something like subset sum will work.

0 replies
Victim |Level 1
3 Feb 2021
Comment Removed
1 upvote
0 replies
6 Nov 2020
Comment Removed
0 replies
9 days ago

Count special nodes in Generic tree Solution

``````void dfs(TreeNode<int> *root, unordered_set<int> &pathElements, int &count){
if(!root){
return;
}
int currVal = root->data;
if(pathElements.count(currVal) != 0){
retur...``````
See more
0 replies
2 months ago
``````#include <unordered_map>

bool isAnagram(string str1, string str2)
{
unordered_map<char, int>mp;
if(str1.length()==str2.length())
{
for(int i=0;i<str1.length();i++)
{
mp[str1[i]]++;
mp[str2[i]]++;
}
for(auto i:mp)
{
if(i.second ...``````
See more